What is the sum of the number between 400 and 500 such that when they are divided by 6, 12 and 16, it leaves no remainder?
Show answer & explanation
Correct answer: A
Explanation
The correct answer is option 1 i.e. 912
We need to find the sum of numbers in the range of 400 - 500 such that they are divisible by each 6, 12, and 16.
LCM (6, 12, 16) = 48k
The required numbers will be in the form of 48k, where k is a natural number.
For k = 9
48k = 48 × 9 = 432
For k = 10
48k = 48 × 10 = 480
Only 432 and 480 are the number that is between 400 and 500, and also divisible by 6, 12 and 16
Sum = 432 + 480 = 912