SSC CGL 2022 PYQ — Question 56

SSC CGL - 21 April 2022 - Shift 2 • Quantitative Aptitude • Q56

A solid cone of radius 7 cm and height 7 cm was melted along with two solid spheres of radius 7 cm each to form a solid cylinder of radius 7 cm. What is the curved surface area (in cm2) of the cylinder? (Use π = 227\frac{22}{7})

Show answer & explanation

Correct answer: C

Explanation

The correct answer is Option 3 i.e. 924.

A solid cone of radius 7 cm and height 7 cm was melted along with two solid spheres of radius 7 cm each to form a solid cylinder of radius 7 cm.

The volume of a cone = 1/3πr2h

The volume of a cylinder = πr2h

The volume of a sphere = 4/3πr3

The curved surface area of a cylinder = 2πrh (Here, r = radius, h = height)

The volume of the cone = 1/3π × 72 × 7 = 1/3π × 73

The volume of each sphere = 4/3π × 73

Let the height of the formed cylinder be H

According to the question -

⇒ 1/3π × 73 + 2 × 4/3π × 73 = π × 72 × H

⇒ 73π(1/3 + 8/3) = π × 72 × H

⇒ 7 × (9/3) = H

⇒ 7 × 3 = H

⇒ 21 = H

So, the height of the formed cylinder is 21 cm

The curved surface area of the cylinder

⇒ 2 × 22/7 × 7 × 21 = 924 cm2