SarkariPYQ

SSC CGL 2022 PYQ — Question 63

SSC CGL - 13 April 2022 - Shift 2 • Quantitative Aptitude • Q63

Back to paper

The value of 48.3×[(4.95)2+4.95×13.25][(12.252−(5.65)2]×19.8\dfrac{48.3\times[(4.95)^2+4.95\times13.25]}{[(12.25^2-(5.65)^2]\times19.8}is:

Show answer & explanation

Correct answer: C

Explanation

The correct answer is option 3 i.e. 1.75

Explanation:

We have given 48.3×[(4.95)2+4.95×13.25][(12.552−(5.65)2]×19.8\dfrac{48.3\times[(4.95)^2+4.95\times13.25]}{[(12.55^2-(5.65)^2]\times19.8}

⇒ 48.3×4.95(4.95+13.25)(12.55+5.65)(12.55−5.65)×19.8\dfrac{48.3\times4.95(4.95+13.25)}{(12.55+5.65)(12.55-5.65)\times19.8}

⇒ 48.3×4.95(18.20)(18.20)(6.9)×19.8\dfrac{48.3\times4.95(18.20)}{(18.20)(6.9)\times19.8}

⇒  34.65/19.8 = 1.75

Hence the value of 48.3×[(4.95)2+4.95×13.25][(12.552−(5.65)2]×19.8\dfrac{48.3\times[(4.95)^2+4.95\times13.25]}{[(12.55^2-(5.65)^2]\times19.8} is 1.75.