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SSC CGL 2022 PYQ — Question 62

SSC CGL - 13 April 2022 - Shift 2 • Quantitative Aptitude • Q62

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The expression (cos6θ + sin6θ-1)(tan2θ + cot2θ + 2) + 3 is equal to:

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Correct answer: A

Explanation

The correct answer is option 1 i.e. 0

(cos6θ + sin6θ-1)(tan2θ + cot2θ + 2) + 3

Here put θ = 45°

= (cos6 45° + sin6 45° - 1)(tan245° + cot245° + 2) + 3

= {(12)6+(12)6−1(\frac{1}{\sqrt2})^6+(\frac{1}{\sqrt2})^6-1} (1 + 1 + 2) + 3

= {(1/4) - 1}(4) + 3

= (-3/4)(4) + 3

= 0