SSC CGL 2021 PYQ — Question 71

SSC CGL - 17 Aug 2021 - Shift 1 • Quantitative Aptitude • Q71

The value of 32 ÷ 12 of 3 × [5 – (15 – 12) ÷ 9] of 37\frac37 + 4 – 8 ÷ 2 of 4 is:

Show answer & explanation

Correct answer: B

Explanation

The correct answer is Option 2 i.e  4794\frac79

One can solve this question by using the concept of BODMAS

⇒ 32 ÷ 12 of 3 × [5 – (15 – 12)  ÷  9] of 37\frac37  +  4 – 8 ÷ 2 of 4

⇒ 32 ÷ 12 of 3 ×  [5 – 3 ÷ 9] of 37\frac37  +  4 – 8 ÷ 2 of 4

⇒ 32 ÷ 12 of 3 ×14/3 of 37\frac37 + 4 – 8 ÷ 2 of 4

⇒ 32 ÷ 12 of 3 × 2 + 4 – 8 ÷ 2 of 4

⇒ 32 ÷ 36 × 2 + 4 – 8 ÷ 8

⇒ 16/9 + 4 – 1

⇒ 4794\frac{7}{9}