In a triangle ABC, a point D lies on AB and points E and F lie on BC such that DF is parallel to AC and DE is parallel to AF. If BE = 4 cm. EF = 6cm, then find the length (in cm) of BC.
Show answer & explanation
Correct answer: C
Explanation
The correct answer is Option 3 i.e 25.

Here DE is parallel to AF so one can say that,
BDE and ABF are similar by AA similarity.
BE/BF = BD/AB = 4/10 = 2/5.............(1)
Here DF is parallel to AC so one can say that,
BDF is similar to ABC by AA similarity.
BF/BC = BD/BA = 10/x..............(2)
From eq 1 and 2 we get,
2/5 = 10/x
x = 50/2 = 25 cm.