A certain number of student from school X appeared in an examination and 20% students failed. From school Y. 130% more students than that school X, appeared in the same examination. If 90% of the total of students appeared from both the schools passed, then what is the percentage of students from school Y who failed (correct to one decimal place)?
Show answer & explanation
Correct answer: C
Explanation
The correct answer is Option 3 i.e 5.7%
Let the number of students in School X = 100a
The number of students in School Y = 230a. (130% more than X)
20% students of School X are failed = 20a
Number of students from school X who pass the examination = 100a - 20a = 80a.
Total number of students from school X and Y = 330a
90% of total students passed the examination = 90/100 × 330a = 297a
Number of students who pass from School Y = 297a - 80a = 217a
Number of students who failed from School Y = 230a - 217a = 13a.
Percentage of students from school Y who failed the examination = 13a / 230a × 100 = 5.7%