SarkariPYQ

SSC CPO 2019 PYQ — Question 124

SSC CPO Tier I - 12th December 2019 - Shift 1 • Quantitative Aptitude • Q124

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The value of {(0.13)2 + (0.21)2}/{(0.39)2 - 81(0.07)2} ÷ {(2.4)4 + 3 × (11.52) + 9
}/{2.4)6 + 6(2.4)4 + 3(17.28)} lies between?

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Correct answer: B

Explanation

The correct answer is Option 2 i.e. 0.6 and 0.7

Application

{(0.13)2 + (0.21)2}/{(0.39)2 - 81(0.07)2} ÷ {(2.4)4 + 3 × (11.52) + 9}/{2.4)6 + 6(2.4)4 + 3(17.28)}

= {(0.13)2 + (0.21)2}/{(0.39)2 - 81(0.07)2} ÷ {2.4)6 + 6(2.4)4 + 3(17.28)}/{(2.4)4 + 3 × (11.52) + 9)}

= (0.061/0.549) × (276.1176/49.32)

= 16.84317/27.07668

= 0.6222

Hence it lies between 0.6 and 0.7