An observer who is 1.62 m tall is 45 m away from a pole. The angle of elevation of the top of the pole from his eyes is 30°. The height(in m) of the pole is closest to?
Show answer & explanation
Correct answer: D
Explanation
The correct answer is option 4 i.e. 27.6
| Application |
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Let ED is an observer who is 1.62 m tall is 45 m away from a pole AC as shown in the figure:
Here, DC = EB = 45m ED = BC = 1.62 m Let AB = x meter In right-angled triangle ABE Tan 30° = AB/EB = X/45 X = 45/√3 = 45√3/3 = 15√3 metres Height (in m) of the pole = 15√3 + 1.62 = 15 × 1.73 + 1.62 = 27.6 metres |
