SSC CGL 2022 PYQ — Question 11

The correct answer is option 4 i.e. 25.9

$\pi rl$ = 2310 and r = 21 cm.

22/7 × 21 × l = 2310

l = 35 cm.

The height of the circular cone = $\sqrt{l^2 - r^2}$

h = $\sqrt{35^2 - 21^2}$

h = 28 cm.

If its radius is increased by 100% and height is reduced by 50% then,

r = 42cm and h = 14 cm.

Volume of cone = $\frac{1}{3}\pi r^2h$

Volume of the cone = 1/3 × 22/7 × 42 × 42 × 14 = 25872 cm³.

One knows that,

1 cm³ = 1 ml

25872 cm³ = 25872/1000 = 25.872 l

= 25.9 liters.