SSC CGL 2022 PYQ — Question 74

The correct answer is Option 4 i.e. 28 cm.

Area of sector = 308 cm²

Central angle = 45°

Area of sector = ${\theta \over 360^0} \times \pi r^2$     ...(i)

Putting the given values in equation (i), we get

Area of sector = ${45\over 360} \times {22 \over 7} \times r^2$ 

⇒ 308 = ${1 \over 8} \times {22 \over 7} \times r^2$
⇒ r² = 56 × 14

⇒ r² = 49 × 16

⇒ r = 28

Hence the radius of the sector is 28 cm.