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SSC CHSL 2023 PYQ — Question 61

SSC CHSL - 04 Aug 2023 - Shift 4 • Quantitative Aptitude • Q61

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Simplify: (612+388)2+(612−388)2(612x612)+(388x388)=?\frac{(612+388)^2+(612-388)^2 }{ (612x612)+(388x388) }=?

Show answer & explanation

Correct answer: C

Explanation

The correct answer is option 3 i.e. 2.

Given that

(612+388)2+(612−388)2(612x612)+(388x388)=?\frac{(612+388)^2+(612-388)^2 }{ (612x612)+(388x388) }=?

Formula used

(a + b)2 = a2 + b2 + 2ab

(a - b)2 = a2 + b2 - 2ab

Calculation

⇒ [6122 + 3882 + 2(612 × 388) + 6122 + 3882 - 2(612 × 388)]/[6122 + 3882]

⇒ 2[6122 + 3882]/[6122 + 3882]

⇒ 2