In the given figure, ABCD is a square whose side is 4 cm. P is a point on the side AD. What is the minimum value (in cm) of 2(BP + CP)?
Show answer & explanation
Correct answer: A
Explanation
The correct answer is Option 1 i.e. 8√5.
CD = 4 cm
It will be minimum when P is the midpoint of DA
⇒ AP = PD = 2 cm
So,
CP = √(16 + 4) = √20 = 2√5
And
BP = 2√5
Hence,
CP + BP = 4√5
2(CP + BP) = 8√5