ABC is a right angled triangle. ∠BAC = 90° and ∠ACB = 60°. What is the ratio of the circum radius of the triangle to the side AB?
Show answer & explanation
Correct answer: B
Explanation
The correct answer is option 2 i.e. 1 : √3
Circumradius = hypotenuse/2
sin60° = AB/BC
⇒ √3/2 = AB/H
⇒ √3/2 = AB/2R
⇒ R = AB/√3
⇒ R/AB = 1/√3