In the given figure, ABCD is a rectangle and P is a point on DC such that BC = 24 cm, DP = 10cm, and CD = 15 cm. If AP produced intersects BC produced at Q, then find the length of AQ.

Show answer & explanation
Correct answer: C
Explanation
The correct answer is option 3 i.e. 39 cm

In the given figure one can see that,
CP || AB.
So one can say that ABQ and PCQ are similar,
PC/AB = CQ/BQ = PQ/AQ
Let CQ = x cm.
PC/AB = CQ/BQ
5/15 = x/(24 + x)
3x = x + 24
2x = 24
x = 12.
In PCQ
PC = 5 and CQ = 12 then hypotenuse PQ = = 13
PQ = 13
PC/AB = PQ/AQ
1/3 = 13/AQ
AQ = 39 cm.