In ΔPQR, ST is parallel to QR. If PS = 5 cm, SQ = 10 cm, and PT = 6 cm, find TR.
Show answer & explanation
Correct answer: C
Explanation
The correct answer is option 3 i.e. 12 cm.
In ΔPQR, ST is parallel to QR
PS = 5 cm, SQ = 10 cm, PT = 6 cm
By Basic Proportionality Theorem: PS/SQ = PT/TR
⇒ 5/10 = 6/TR
⇒ 1/2 = 6/TR
⇒ TR = 12 cm