SSC CGL 2025 PYQ — Question 52

The correct answer is option 1 i.e. 5 + 2$\sqrt6$.

$(a + b)^2 = a^2 + 2ab + b^2$

$(\sqrt{3} + \sqrt{2})^2$

$= (\sqrt{3})^2 + (\sqrt{2})^2 + 2 \times \sqrt{3} \times \sqrt{2}$

$= 3 + 2 + 2\sqrt{6}$

$= 5 + 2\sqrt{6}$