SSC CHSL 2020 PYQ — Question 71

SSC CHSL - 13th October 2020 - Shift 2 • Quantitative Aptitude • Q71

If x4 + 1/x4 = 257/16 then find 8/13  where x > 0.

Show answer & explanation

Correct answer: D

Explanation

The correct answer is option 4 i.e 5

Understanding Application
We will use the identity of (a + b)2 to solve the algebraic equation.

We have given that,

⇒ x4 + 1/x4 = 257/16

Adding two in both the sides

⇒  x4 + 1/x4 + 2 = 257/16 + 2

⇒ (x2 + 1 / x2)2 = 289 / 16

⇒ x2 + 1 / x2 = 17 / 4

Adding two in both sides of the equation,

⇒ x2 + 1 / x2 + 2 = 17 / 4 + 2

⇒ (x + 1 / x)2 = 25 / 4

⇒ x + 1 / x = 5 / 2

⇒ (x  + 1 / x)3 = x3 + 1 / x3 + 3(x  + 1 / x)

⇒ 125 / 8 = x3 + 1 / x3 + 3(5 / 2)

⇒ x3 + 1 / x3 = 125 / 8 - 15 / 2 = 65 / 8

⇒ (8 / 13) × 65 / 8 = 5