A can finish a piece of work in a certain number of days. B takes 45% more days to finish the same work independently. They worked together for 58 days and then the remaining work was done by B alone in 29 days. In how many days could A have completed the work, had he worked alone?
Show answer & explanation
Correct answer: B
Explanation
The correct answer is option 2 i.e 118 days
Let the number of days A completed his work be 'x' then the number of days B took to complete the work = '1.45x'.
The equation will become by the given condition,
58(1 / x + 1 / 1.45x) + 29(1 / 0.45x) = 1
⇒ (1 / x)(58 + 40 +20) = 1
⇒ x = 118