If in the given figure, ∠ACB + ∠BAC = 80ᵒ; ∠BDE = 35ᵒ; ∠BCE = 45ᵒ , then the marked angle ∠CED is: [Image]

If in the given figure, ∠ACB + ∠BAC = 80ᵒ; ∠BDE = 35ᵒ…

If in the given figure, ∠ACB + ∠BAC = 80^o; ∠BDE = 35^o; ∠BCE = 45^o , then the marked angle ∠CED is:

Show answer & explanation

Correct answer: B

Explanation

The correct answer is option 2 i.e 160^o

Understanding

Application

We will use the property of exterior angle in which the exterior angle of a triangle is equal to the sum of the interior opposite angles.

We have given that

∠ACB + ∠BAC = 80^o

∠BDE = 35^o

∠BCE = 45^o

We will join E to F which will be as

⇒∠DBC = ∠ACB + ∠BAC

⇒ ∠DBC = 80^o

⇒ ∠CFD = 125^o

⇒ ∠CED = 125 + 35 = 160^o