If 117 Cos2 A + 129 Sin2 A = 120 and 170 Cos2 B + 158 Sin2 B = 161, then the value of Cosec2 A Sec2 B is:
Show answer & explanation
Correct answer: D
Explanation
The correct answer is option 4 i.e 16
| Understanding | Application |
| We will use basic trigonometric identities to find the correct answer. |
We have given that ⇒ 117 Cos2 A + 129 Sin2 A = 120 ⇒ 117 + 12 Sin2 A = 120 ⇒ Sin2 A = 1 / 4 ⇒ Cosec2 A = 4 ⇒ 170 Cos2 B + 158 Sin2 B = 161 ⇒ 158 + 12 Cos2 B = 161 Cos2 B = 1 / 4 Sec2 B = 4 ⇒ Cosec2 A Sec2 B ⇒ 4 × 4 = 16 |