If cotθ = 1/√3, then find the value of [(2 - sin2θ)/(1 - cos2θ)] + (cosec2θ + secθ).
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Correct answer: B
Explanation
The correct answer is option 2 i.e. 5.
Given cotθ = 1/√3
Hence, θ = 60°
[(2 - sin2θ)/(1 - cos2θ)] + (cosec2θ + secθ)
Putting θ = 60°,
⇒ [(2 - 3/4)/(1 - 1/4)] + (4/3 + 2)
⇒ [(5/4)/(3/4)] + (4/3 + 2)
⇒ 5/3 + 4/3 + 2
⇒ 9/3 + 2 = 15/3
⇒ 5