If a2 + b2 + 64c2 + 16c + 3 = 2(a + b), then the value of 4a7 + b7 + 8c2 is:
Show answer & explanation
Correct answer: C
Explanation
Correct Answer is option 3 i.e. ![]()
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Understanding |
Application |
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Given: a2 + b2 + 64c2 + 16c + 3 = 2(a + b) |
a2 + b2 + 64c2 + 16c + 3 = 2(a + b) ⇒ a2 + b2 + (8c)2 + 16c + 3 – 2a – 2b = 0 ⇒ a2 – 2a + 1 + b2 – 2b + 1 + (8c)2 + 16c + 1 = 0 ⇒ (a – 1)2 + (b – 1)2 + (8c + 1)2 = 0 ⇒ a = 1, b = 1 and c = -1/8 Hence, 4a7 + b7 + 8c2 = 4 × 1 + 1 + 8 × 1/64 = |