The value of θ, when √3cos θ + sin θ = 1 (0° ≤ θ ≤ 90°), is?
Show answer & explanation
Correct answer: A
Explanation
Correct Answer is option 1 i.e. 90°
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Understanding |
Application |
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Given √3cosθ + sinθ = 1 (0° ≤ θ ≤ 90°) |
√3cosθ + sinθ = 1 Checking all the options: Put θ = 90° ⇒ √3cos90 + sin90 ⇒ √3 × 0 + 1 ⇒ 1 Hence, option 1 is correct. |