The correct answer is option 1 i.e. 3
let's, 1−sinθ1+1+sinθ1=4secθ,(0<θ<90)
⇒ (1−sinθ)(1+sinθ)(1+sinθ)+(1−sinθ)=4secθ
⇒ (1−sin2θ)2=cosθ4
⇒ 4 cos2θ = 2cosθ
⇒ cosθ = 1/2
⇒ θ = 60°
then, (cot60° + cosec60°)
⇒ 31+32
⇒ 33 = 3
So the expected answer is 3.