Find the smallest number that is exactly divisibly by 12, 15, 18, and 27.
Show answer & explanation
Correct answer: C
Explanation
The correct answer is Option 3 i.e. 540.
L.C.M(12, 15, 18, and, 27)
⇒ 12 = 2 × 2 × 3
⇒ 15 = 3 × 5
⇒ 18 = 2 × 3 × 3
⇒ 27 = 3 × 3 × 3
So, 3 × 3 × 2 × 2 × 5 × 3 = 540
Hence,
The smallest number that is exactly divisibly by 12, 15, 18, and 27 = 540