ΔABC is an isosceles triangle inscribed in a circle. If AB = AC = 12√5 cm and BC = 24 cm then find the radius of the circle.
Show answer & explanation
Correct answer: B
Explanation
The correct answer is option 2 i.e. 15 cm.

AD is perpendicular to BC:
Given, BC = 24 cm
BD = DC = 12 cm
OC = OA = Circumradius = r cm
AD = √[AB2 - BD2]
⇒ AD = √[(12√5)2 - (12)2]
⇒ AD = √[144 × 5 - 144]
⇒ AD = √[144 × 4] = 24 cm.
In triangle OCD,
OD = (24 - r) cm.
OC2 = OD2 + CD2
⇒ r2 = (24 – r)2 + 122
⇒ r2 = 576 – 48r + r2 + 144
⇒ 48r = 720
⇒ r = 720/48 = 15 cm