ABC is an isosceles triangle where AB = AC which is circumscribed about a circle. If P is the point where the circle touches the side BC, then which of the following is true ?
Show answer & explanation
Correct answer: A
Explanation
The correct answer is option 1 i.e BP = PC
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Here given that = AB = AC AQ + BQ = AR + RC We know that: BQ = PB and PC = RC AQ + PB = AR + PC Also AQ = AR ⇒ AR + PB = AR + PC ⇒ BP = PC |
