A and B are the centers of two circles with radii 11 cm and 6 cm respectively. A common tangent touches these circles at P & Q respectively. If AB =13 cm, then the length of PQ is:
Show answer & explanation
Correct answer: D
Explanation
The correct answer is option 4 i.e. 12 cm
| Application |
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Here, AB = 13 cm. PQ = √[(AB)² - (r1 - r2)²] ⇒ PQ = √[(13)² - (11 - 6)²] ⇒ PQ = √[169 -25] = √144 = 12 cm. |
