AB and AC are two tangents to a circle whose radius is 6 cm. If ∠BAC = 60°, then what is the value (in cm) of √(AB² + AC²) ?
Show answer & explanation
Correct answer: A
Explanation
The correct answer is option 1 i.e. 6√6.
tan60° = AB/BO
⇒ √3 = AB/6
⇒ AB = 6√3 = AC
Hence,
√(AB² + AC²) = √[(6√3)² + (6√3)²] = 6√6 cm