SSC CHSL 2020 PYQ — Question 55

SSC CHSL - 14th October 2020 - Shift 2 • Quantitative Aptitude • Q55

A train travels the distance between stations P and Q at a speed of 126 km/h, while in the opposite direction it comes back at 90 km/h. Another train travels the same distance at the average speed of the first train. The time taken by the second train to travel 525 km is:

Show answer & explanation

Correct answer: A

Explanation

The correct answer is option 1 i.e 5 hours.

Understanding Application

Average speed = Total distance/Total time 

Let the distance between P and Q is D.

Total distance= D + D = 2D

As we know Speed = Distance / Time

So, Time = Distance / Speed

S1 = 126 km/h

S2 = 90 km/h

Time taken by the first train to travel P to Q (T1)= D/126

Time taken by the first train to travel Q to P(T2) = D/90

Total time = T1 + T2

Total time = (D/126) + (D/90) = 12D/630

Average speed of the train = 2D/(12D/630) = 105 km/hr

Speed of the second train = Average speed of first train = 105 km/h

Time taken by second train = Distance / Speed = 525 / 105 = 5 hours