SSC CHSL 2020 PYQ — Question 54

SSC CHSL - 14th October 2020 - Shift 2 • Quantitative Aptitude • Q54

In the given figure, if AD = 3, DE = 4, AB = 12, BF = 2, FG = 6, BC = 10, then the value of M/N is:

(Assume : M is the area of the quadrilateral FGDE and N is the area of the triangle ABC.)

Show answer & explanation

Correct answer: A

Explanation

The correct answer is option 1 i.e 31/60.

Understanding Application

M = Area of queadrilateral FGDE = Area of triangle DBG - Area of triangle EBF

Area of triangle = (1/2) x Multiple of adjacent sides x sin ( Angle between those sides)

BE= AB - AD - DE

Area of triangle EBF = (1/2) x BE x BF x sinB

= (1/2) x 5 x 2 x sinB = 5 x sinB

Area of triangle ABC = (1/2) x 12 x 10 x sinB 

= 60 x sinB

M = Area of queadrilateral FGDE = Area of triangle DBG - Area of triangle EBF = 36 sinB - 5sinB = 31 sinB

M/N = Area of queadrilateral FGDE / Area of triangle ABC = 31 sinB/60 sinB = 31/60