SSC Selection Post 2020 PYQ — Question 57

SSC Selection Post - Matriculation Level 2020 - 10 Nov 2020 - Shift 1 • Quantitative Aptitude • Q57

A shopkeeper fixes the marked price of his goods at 25% above the cost price. He sells 60% of the goods at the marked price and the rest at a discount of 40%. What is his gain/loss percentage?

Show answer & explanation

Correct answer: A

Explanation

The correct answer is option 1 i.e. Gain: 5%.

Marked Price (MP) = ₹100 + 25% of 100 = ₹125

Selling price = 60% of  ₹125 = 0.60 × 125 = ₹75

These are sold at 40% discount on MP, so:

Selling Price = 60% of MP = 0.60 × 125 = ₹750

Selling price = 40% of ₹75 = 0.40 × 75 = ₹30

Total CP = ₹100 (for full goods)

Total SP = ₹75 (from 60% sold at MP) + ₹30 (from 40% sold at discount) = ₹105

Profit = ₹105 - ₹100 = ₹5

Profit % = 5100×100=5% \frac{5}{100} \times 100 = 5\%