The value of 252\over552 ÷ 3103\over10 103 of 494\over994 − 454\over554 × 1191\over991÷ 8158\over15158 − 343\over4 43 +343\over4 43 ÷ 121\over2 21is ? A797\over9 97 B23623\over6623 C434\over3 34 D−35108 \frac{-35}{108}108−35 Show answer & explanationCorrect answer: DExplanationThe correct answer is option 4 i.e. −35108 \frac{-35}{108}108−35. 25÷310⋅49−45⋅119÷815−34+34÷12\frac{2}{5} \div \frac{3}{10} \cdot \frac{4}{9} - \frac{4}{5} \cdot 1\frac{1}{9} \div \frac{8}{15} - \frac{3}{4} + \frac{3}{4} \div \frac{1}{2}52÷103⋅94−54⋅191÷158−43+43÷21 ⇒ 25⋅103⋅49−45⋅109⋅158−34+34⋅21\frac{2}{5} \cdot \frac{10}{3} \cdot \frac{4}{9} - \frac{4}{5} \cdot \frac{10}{9} \cdot \frac{15}{8} - \frac{3}{4} + \frac{3}{4} \cdot \frac{2}{1}52⋅310⋅94−54⋅910⋅815−43+43⋅12 ⇒ 1627−53−34+32\frac{16}{27} - \frac{5}{3} - \frac{3}{4} + \frac{3}{2} 2716−35−43+23 The LCM of 27, 3, 4 and 2 is 108. ⇒ 64108−180108+81108+162108=(64−180+81+162)108=−35108\frac{64}{108} - \frac{180}{108} + \frac{81}{108}+ \frac{162}{108} = \frac{(64 - 180 + 81 +162)}{108} = \frac{-35}{108}10864−108180+10881+108162=108(64−180+81+162)=108−35