SSC CGL 2025 PYQ — Question 52

The correct answer is option 2 i.e. $(6\pi - 9\sqrt{3})$ cm².

Area of sector = $60\over360$ × π × 6²

⇒ $1\over6$ × π × 36 = 6π

Area of triangle = $1\over2$ × 6 × 6 × sin60°

⇒ 18 × $√3\over2$ = 9√3

Area of segment = Sector − Triangle

⇒ 6π − 9√3 cm²