SSC CGL 2025 PYQ — Question 51

SSC CGL - 15 Sep 2025 - Shift 2 • Quantitative Aptitude • Q51

Express 0.121212..... as a fraction.

Show answer & explanation

Correct answer: A

Explanation

The correct answer is option 1 i.e. 433{4 \over 33}.

Let x = 0.121212…

Multiply by 100 

100x = 12.121212…

Now subtract:

⇒ 100x − x = 12.121212… − 0.121212…

⇒ 99x = 12

⇒ x = 1299{12 \over 99} = 433{4 \over 33}