SSC CHSL 2019 PYQ — Question 62

SSC CHSL - 9th July 2019 - Shift 1 • Quantitative Aptitude • Q62

A dealer buys an article marked at Rs.30000 with two successive discounts of 20% and 5%. How spends Rs.1200 on repairs and sells it for Rs.30000, what is his profit/loss percent?

Show answer & explanation

Correct answer: B

Explanation

Correct Answer is option 2 i.e. 25% profit

Understanding

Application

Cumulative discount after 2 successive discounts of x and y% = x + y - xy/100

MP = 30000

Two successive discounts of 20% and 5%

Expenses on repairs = 1200

SP = 30000

 

Cumulative discount = 20 + 5 – 100/100 = 24%

Hence,

CP = 30000 × 0.76 = 22800

Additional expenditure = 1200

So, total C.P of article = 22800 + 1200 = 24000

Profit % = [(30000 – 24000/24000)] × 100 = 25%