SSC CHSL 2019 PYQ — Question 61

SSC CHSL - 9th July 2019 - Shift 1 • Quantitative Aptitude • Q61

If cosθ = 4x and sinθ = 4/x, x ≠ 0, then the value of (1/x2 + x2) is:

Show answer & explanation

Correct answer: A

Explanation

Correct Answer is option 1 i.e. 1/16

Concept

Understanding

Application

Sin2θ + cos2θ = 1

Given

cos θ = 4x and sin θ = 4/x,

x ≠ 0

Hence,

(4/x)2 + (4x)2 = 1

⇒ 16 (1/x2 + x2) = 1

⇒ (1/x2 + x2) = 1/16