A can do a work in 7 hours and B can do the same work in 10 hours. If they work together for 3 hours, then what part of the work will be left out?
Show answer & explanation
Correct answer: A
Explanation
The correct answer is option 1 i.e.
Time taken by A = 15/2 hours
Time taken by B = 21/2 hours
Let total work = 105 units [Multiple of 15 and 21]
Work done by A per hour work = 105/(15/2) = 14 units
Work done by B per hour work = 105/(21/2) = 10 units
Their total work in 7/2 hours = (24) × (7/2) = 84 units
Work left = (105 - 84) = 21 units
The remaining work = 21/105 = 1/5