The value of 12.5+45 of 56−12(207÷23×4.5)−2113×(14+18)\frac{12.5+\frac{4}{5} \ of \ 56-12}{(207\div23\times 4.5)-21 \frac{1}{3}\times (\frac{1}{4}+\frac{1}{8})}(207÷23×4.5)−2131×(41+81)12.5+54 of 56−12 is: A4 B1 C2 D5 Show answer & explanationCorrect answer: BExplanationThe correct answer is option 2 i.e. 1 ⇒12.5+47 of 56−12(207÷23×4.5)−2113×(14+18)⇒\frac{12.5 + \frac{4}{7} \ of \ 56 - 12}{(207 \div 23 \times 4.5) - 21 \frac{1}{3} \times \left( \frac{1}{4} + \frac{1}{8} \right)} ⇒(207÷23×4.5)−2131×(41+81)12.5+74 of 56−12 ⇒12.5+32−12(9×4.5)−2113×( 38) ⇒\frac{12.5 + 32 - 12}{(9 \times 4.5) - 21 \frac{1}{3} \times \left(\ \frac{3}{8} \right)} ⇒(9×4.5)−2131×( 83)12.5+32−12 ⇒12.5+20(9×4.5)−643×( 38) ⇒ \frac{12.5 + 20 }{(9 \times 4.5) - \frac{64}{3} \times \left(\ \frac{3}{8} \right)} ⇒(9×4.5)−364×( 83)12.5+20 ⇒32.5(40.5−8) ⇒\frac{32.5 }{(40.5 - 8 )} ⇒(40.5−8)32.5 ⇒32.532.5⇒ \frac{32.5 }{32.5}⇒32.532.5 ⇒ 111