SSC MTS 2022 PYQ — Question 67

The correct answer is option 4 i.e. 48 s.

Distance = length of train = 600 m

Speed = 45 km/h

Distance = Speed × Time

Time = $Distance\over Speed$

Speed(in m/s) = Speed(in km/h) $\times {5 \over 18}$

According to the given question,

Speed of train(in m/s) = 45 $\times {5 \over 18}$ = $25 \over 2$ = 12.5 m/s

Now, time = $600 \over 12.5$ = 48 s

Hence the required time is 48 s.