SSC MTS 2022 PYQ — Question 68

SSC MTS - 18 July 2022 - Shift 2 • Quantitative Aptitude • Q68

Samira can do a piece of work in 9 days. Sujata can do 13\frac{1}{3} of the same work in 3 days. If Samira worked alone for 2 days and left, then in how many days can Sujata alone complete the remaining work?

Show answer & explanation

Correct answer: D

Explanation

The correct answer is option 4 i.e. 7 days.

Concept Used:

Total work = Number of days × Efficiency

Calculations:

Samira can do the work in 9 days

Sujata can do (1/3) work in 3 days

Sujata can do the whole work in 3 × 3 = 9 days.

Total work = LCM of (9, 9) = 9 units

Efficiency of Samira = Efficiency of Sujata = 9/9 = 1 unit/day

Samira worked for 2 days, the amount of work completed = 2 × 1 = 2 units

Remaining work = 9 - 2 = 7 units

Now, the time taken by Sujata to complete the remaining work = 7/1 = 7 days

Hence the required time is 7 days.