Which of the following is true when x = SinA + CosA; y = SecA + CosecA?
Show answer & explanation
Correct answer: A
Explanation
The correct answer is Option 1 i.e. y + 2x = x2 y.
Given that
x = SinA + CosA
Squaring both sides we get
x2 = sin2A + cos2A + 2sinAcosA
Formula used
sin2A + cos2A = 1
x2 = 1 + 2sinAcosA
Now, x2y = ( 1 + 2sinAcosA )( secA + cosecA )
Multiplying be we
secA + cosecA + 2sinA + 2cosA
⇒ secA + cosecA + 2( sinA + cosA )
⇒ y + 2x
Hence, y + 2x = x2y.