Which is the largest six-digit number, which when divided by 12, 15, 20, 24 and 30, leaves the remainders 8, 11, 16, 20 and 26 respectively.
Show answer & explanation
Correct answer: B
Explanation
The correct answer is option 2 i.e. 999956
LCM of 12, 15, 20, 24 and 30 = 120
6 digit largest number = 999999
when we divided 999999 by 120 it will gives 39 as a remainder.
12 - 8 = 4, 15 - 11 =4, 20 - 16 = 4, 24 - 20 = 4 and 30 - 26 = 4
So, the required number = 999999 - (39 + 4) = 999956