Whatis the greatest number by which when 156, 181 and 331 are divided, the remainder is 6 in each case ?
Show answer & explanation
Correct answer: B
Explanation
The correct answer is option 2 i.e. 25
Solution :
The greatest number that will divide x, y and z leaving a same remainder in each case is given by HCF of |x - y|, |y -z| and |z - x|
Given that x = 156 y = 181 and z = 331
|156 -181| = |-25| = 25
|181 - 331| = |-150| = 150
|331 - 156| = 175
Now HCF(25, 150, 175) = 25.
Hence the required number is 25.