What number must be added to each of the numbers 8, 13, 26 and 40 so that the numbers obtained in this order are in proportion?
Show answer & explanation
Correct answer: B
Explanation
The correct answer is Option 2 i.e 2.
| Understanding/Application |
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Let the number added be x. 8 + x, 13 + x, 26 + x, 40 + x |
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(8 + x)/(13 + x) = (26 + x)/(40 + x) (8 + x) (40 + x) = (26 + x) (13 + x) 320 + 8x + 40x + x2 = 338 + 26x + 13x + x2 320 + 48x = 338 + 39x 48x - 39x = 338 - 320 9x = 18 x = 2 |