SSC CGL 2024 PYQ — Question 51

The correct answer is option 4 i.e.  9$\pi$.

r = 3 units, l = 3√2 units

So, the height of the cone $(h)=\sqrt{l^2-r^2}=\sqrt{(3\sqrt2)^2-3^2}=\sqrt{18-9}=\sqrt9=3$ cm

Volume $=\frac{1}{3}\pi r^2h$ = (1/3) × π × (3)² × 3 = 9π cubic units