What is the value of tan9∘tan23∘tan60∘tan67∘tan81∘cosec272∘+cos215∘−tan218∘+cos275∘\frac{tan9^\circ tan23^\circ tan60^\circ tan67^\circ tan81^\circ}{cosec^272^\circ+cos^215^\circ-tan^218^\circ+cos^275^\circ}cosec272∘+cos215∘−tan218∘+cos275∘tan9∘tan23∘tan60∘tan67∘tan81∘ A123\frac{1}{2\sqrt3}231 B32\frac{\sqrt3}{2}23 C13\frac{1}{\sqrt3}31 D232\sqrt323 Show answer & explanationCorrect answer: BExplanationThe correct answer is Option 2 i.e. 32\frac{\sqrt3}{2}23. tan9∘tan23∘tan60∘tan67∘tan81∘cosec272∘+cos215∘−tan218∘+cos275∘\frac{tan9^\circ tan23^\circ tan60^\circ tan67^\circ tan81^\circ}{cosec^272^\circ+cos^215^\circ-tan^218^\circ+cos^275^\circ}cosec272∘+cos215∘−tan218∘+cos275∘tan9∘tan23∘tan60∘tan67∘tan81∘ =tan9∘tan81∘×tan60∘×tan67∘tan23∘sec218∘−tan218∘+sin275∘+cos275∘=\frac{tan9^\circ tan81^\circ \times tan60^\circ \times tan67^\circ tan23^\circ}{sec ^218^\circ-tan^218^\circ+sin^275^\circ+cos^275^\circ}=sec218∘−tan218∘+sin275∘+cos275∘tan9∘tan81∘×tan60∘×tan67∘tan23∘ = tan60°/(1 + 1) = √3/2