if √(8x²)dotplus 3√(3y⁶)= ( Ax²+ By² ) ( Cx⁴+ Dx²y²+ 3y⁴ ) , then the value of ((C-D))/((A+B)) is:

if √(8x²)dotplus 3√(3y⁶)= ( Ax²+ By² ) ( Cx⁴+ Dx²y²+ 3y⁴ )…

if $\sqrt{8x^2}\dotplus 3\sqrt{3y^6}= \left ( Ax^2+ By^2 \right )\left ( Cx^4+ Dx^2y^2+ 3y^4 \right )$ , then the value of $\frac{(C-D)}{(A+B)}$ is:

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Correct answer: B

Explanation

The correct answer is Option 2 i.e. $\sqrt2$ .

√(8x²) + 3√(3y⁶) = (Ax² + By²)(Cx⁴ + Dx²y² + 3y⁴)

⇒ (√2x + √3y)(2x² - √6xy + 3y²) = (Ax² + By²)(Cx⁴ + Dx²y² + 3y⁴)

A = √2, B = √3, C = 2, D = -√6

Now, (C - D)/(A + B) = [2 - (-√6)]/(√2 + √3)

= (2 + √6)/(√2 + √3)

= √2