SarkariPYQ

SSC GD 2024 PYQ — Question 42

SSC GD Const (English) - 21 Feb 2024 - Shift 3 • Quantitative Aptitude • Q42

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What is the value of [289 ÷ {68 ÷ 4 × (14 + 2 × 6 -9)}]?

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Correct answer: C

Explanation

The correct answer is option  3 i.e.  1 .

⇒ [289÷68÷4×(14+2×6−9)][289 ÷ {68 ÷ 4 × (14 + 2 × 6 -9)}]

⇒ [289÷68÷4×(14+12−9)][ 289 ÷ {68 ÷ 4 × (14 + 12 -9)}]

⇒ [289÷68÷4×(14+3)][ 289 ÷ {68 ÷ 4 × (14 + 3 )}]

⇒ [289÷17×17][ 289 ÷ {17 × 17}]

⇒ [289÷289][ 289 ÷ 289 ]

⇒ 1